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Hi.Can anyone help me decode this message.
" h.ktctaei" u ohdys ni l.a"urocfierltogfn i! yg ternrhtig'isu okyoeoh r"
Keep the white space in front of "h" and all the white spaces.
Here is the key:.
It's a sandorf cipher.Here is info about it
http://ruffnekk.stormloader.com/sandorf_info.html
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Ive never seen that before, but on the same website i found this:
http://ruffnekk.stormloader.com/sandorf_tool.html
your cipher must devide by 32, yours is 73 characters long meaning one is incorrect. That array will also probably need to be changed to match your key. Ill look at it later
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h.ktctaei" u ohdys ni l.a"urocfierltogfn i! yg ternrhtig'isu okyoeoh r
this is the cipher
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ive ran out of time for today, but i think im getting closer to cracking it. I think your encode array is:
2,4,9,11,16,20,28,30,32, 0,12,14,17,22,25,27,29,34, 3,5,7,15,19,24,26,31,33, 1,6,8,10,13,18,21,23,35
This is really close. Just testing, i got:
[color=lblue]righty! the string you're looking for nyuiac icalsott.er".id fou h"ekh[/clb]
I think you must've got part of the string you posted on here wrong
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your close try rotating some more and nah the string is correct
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here ive made one just for your encryption key:
http://thisislegal.byethost13.com/s.htm
I added an extra space before your key to get that. Like i said yours should be 72 chars long but its 71.
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This might not be correct, but i think it will be. i tried forming words from the letters left over and try either one of these:
righty! the string you're looking for is "ethical hacker". you found it.
righty! the string you're looking for is "ethicalhacker". you found it.
hope it works
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Gee thanks.I really appreciate your help.
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